Derive the mathematical theorem of Job's method of continuous variations
Consider the general complex formation equilibrium between a metal cation M and a ligand L to form a single complex species ML_n: M + n L ⇌ ML_n, with thermodynamic formation constant Kf = [ML_n] / ([M][L]^n). In Job's method of continuous variations, the sum of the analytical concentrations of metal and ligand is held strictly constant across all solutions: C_M + C_L = C_T = constant. The composition of each solution is defined by the mole fraction of ligand: X_L = C_L / C_T, so that C_L = C_T · X_L and C_M = C_T · (1 - X_L). The mass-balance expressions are [M] = C_M - [ML_n] = C_T(1 - X_L) - [ML_n], and [L] = C_L - n[ML_n] = C_T · X_L - n[ML_n]. To determine the composition where complex concentration [ML_n] achieves an extremum, we differentiate the equilibrium expression Kf = [ML_n] / ([M][L]^n) with respect to X_L and set d[ML_n]/dX_L = 0. Differentiating implicitly yields: [L]^n · d[M]/dX_L + n [M][L]^(n-1) · d[L]/dX_L = 0. Substituting d[M]/dX_L = -C_T and d[L]/dX_L = +C_T: -C_T [L]^n + n C_T [M] [L]^(n-1) = 0. Dividing by C_T [L]^(n-1) simplifies to: -[L] + n [M] = 0, which requires: [L] / [M] = n. At the peak of the Job's curve, the ratio of free ligand to free metal exactly equals the stoichiometric ratio n. Substituting the analytical mole fractions: (C_T · X_L,max) / [ C_T · (1 - X_L,max) ] = n, which rearranges to: X_L,max = n · (1 - X_L,max) = n - n · X_L,max, and finally establishes Job's fundamental theorem: X_L,max = n / (1 + n). For a 1:1 complex (n = 1), the maximum occurs at X_L = 1/2 = 0.500; for a 1:2 complex (n = 2), X_L = 2/3 = 0.667; for a 1:3 complex (n = 3), X_L = 3/4 = 0.750.