EXPERIMENT 17 · PHYSICS LABORATORY
Vector addition and equilibrium of concurrent coplanar forces on a force table
Investigate the static mechanical equilibrium of concurrent coplanar forces using a precision circular force table, verify the parallelogram and polygon laws of vector addition by resolving forces into orthogonal Cartesian components, and determine the unknown magnitude of equal symmetric load forces using ordinary least-squares regression. Explore a virtual apparatus, collect readings and analyse a graph.
FOLLOW THE METHOD
A reason behind every step.
Investigate the static mechanical equilibrium of concurrent coplanar forces using a precision circular force table, verify the parallelogram and polygon laws of vector addition by resolving forces into orthogonal Cartesian components, and determine the unknown magnitude of equal symmetric load forces using ordinary least-squares regression. Suggested independent settings: 20.0, 30.0, 40.0, 50.0, 60.0 °.
1Level the circular force table
Place a circular bullseye spirit level directly onto the center of the force table disk. Adjust the three leveling screws on the tripod base until the spirit level bubble is centered within the target index circle. Rotate the level through 90° to verify that the table is horizontal in all directions.
Why this step matters
Any tilt in the table surface introduces an unmodeled gravitational component acting parallel to the plate, causing the central ring to slide downhill and biasing the force equilibrium measurements.
2Mount the symmetric applied force pulleys
Clamp the first pulley at angle +θ (e.g. 20.0°) and the second pulley at symmetric angle 360° - θ (e.g. 340.0°). Thread two radial cords from the central ring over these pulleys and attach identical total masses M_0 = 150.0 g (including the weight hangers) to both cords.
Why this step matters
Symmetric angular placement forces the lateral orthogonal components to cancel exactly (+M_0 g sin θ - M_0 g sin θ = 0), aligning the net vector resultant R purely along the 0° Cartesian axis.
3Position the equilibrant pulley at 180°
Clamp the third pulley at exactly 180.0° on the table rim, diametrically opposite the 0° line of action of the resultant force. Pass the third cord over this pulley and suspend an empty weight hanger (50.0 g tare).
Why this step matters
Static equilibrium demands an equilibrant vector E that is collinear, equal in magnitude, and oppositely directed to the resultant vector R (E = -R), which corresponds strictly to 180° on the circle.
4Balance the central ring and achieve equilibrium
Carefully add slotted brass weights to the equilibrant hanger until the central ring floats freely and concentrically around the centering pin without contacting it. Tap the rim of the table gently with a pencil to eliminate static bearing friction in the pulley axles.
Why this step matters
Free concentric flotation of the ring without touching the centering pin proves that the net vector sum of the three concurrent tension forces equals zero (Σ F = 0).
5Record equilibrant mass across varying angles
Record the total equilibrant mass m_E (weights plus hanger) to the nearest 0.1 g. Systematically alter the symmetric half-angle setting to θ = 30.0°, 40.0°, 50.0°, and 60.0°. At each setting, adjust the equilibrant mass m_E until the ring is perfectly centered, and record the new balance mass.
Why this step matters
Testing across five distinct angles spans a wide range of cosine values (0.500 to 0.940) and equilibrant masses (150 g to 282 g), providing robust statistical leverage for linear regression.
6Compute trigonometric projection and perform regression
Calculate the independent variable x = cos(θ) for each setting. Convert m_E to kilograms (y = m_E / 1000). Plot y against x, fit an ordinary least-squares regression line, determine the slope S, and compute the estimated component mass M_0 = S / 2.
Why this step matters
Linear regression averages out random ring-centering reading errors and isolates any minor cord tare offsets into the intercept b, yielding an unbiased estimate of M_0 with rigorous confidence intervals.