Physics / Newton’s second law of motion
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EXPERIMENT 20 · PHYSICS LABORATORY

Newton’s second law of motion theory

Understand newton’s second law of motion: the equations, assumptions, supporting concepts and measurement method.

THE WORKING RELATIONSHIP
a = (1 / M_total) · F ⇔ M_total = 1 / S

Keep the physical quantities, graph variables and units consistent.

01Newton's Second Law and the Fundamental Definition of Force

Newton's Second Law of Motion provides the operational and mathematical definition of dynamic force in classical mechanics. In the Principia, Newton stated that the alteration of motion is proportional to the motive force impressed, where 'motion' was defined as the quantity of motion, or linear momentum p = m v. The general vector form of Newton's Second Law is F_net = dp/dt. When the system mass m remains constant during the motion, differentiating the product m v with respect to time yields F_net = m (dv/dt) = m a, where a = d²r/dt² is the instantaneous kinematic acceleration. This formulation establishes that acceleration is not an inherent property of a moving body, but rather the instantaneous dynamical response to an unbalanced external force. Force is an interaction: without a net external force (F_net = 0), acceleration vanishes identically (a = 0), recovering Newton's First Law of Inertia. In SI units, the unit of force—the Newton (N)—is defined as that net force which accelerates a mass of one kilogram at a rate of one meter per second squared: 1 N = 1 kg · m s⁻². In our experimental track system, the monofilament cord applies a horizontal tensile force T to the cart, while gravity pulls downward on the hanging mass with weight W = m_hanger · g, coupling the two bodies into a single co-accelerating dynamic unit.

\vec{F}_{\text{net}} = \frac{d\vec{p}}{dt} = m \frac{d\vec{v}}{dt} = m \vec{a} \implies a = \frac{F_{\text{net}}}{m}
What is the physical distinction between Newton's First Law and Newton's Second Law?

Newton's First Law defines inertial reference frames and qualitative behavior: a body remains at rest or in uniform linear motion unless acted upon by a net external force. Newton's Second Law provides the quantitative, predictive mathematical relationship between the magnitude and direction of the net force and the resulting rate of acceleration: F = m a.

02The Crucial Principle of Constant System Mass in Dynamics

A frequent source of conceptual error in introductory mechanics laboratories is treating the cart as an isolated system subjected to a variable external force. When a hanging mass m_h falls under gravity, the tension in the connecting cord T does not equal the static weight m_h g. Instead, applying Newton's Second Law separately to the cart of mass M_c and the hanging mass m_h yields two coupled equations of motion: for the cart along the horizontal frictionless track, T = M_c · a; for the hanging mass descending vertically, m_h g - T = m_h · a. Adding these two equations eliminates the internal tension T: m_h g = (M_c + m_h) · a. Solving for acceleration yields a = (m_h g) / (M_c + m_h) = F_net / M_total. This reveals that the total mass undergoing acceleration is the sum of the cart mass and the hanging mass: M_total = M_c + m_h. If an experimenter increases the accelerating force by taking additional masses from a storage box and hanging them, both the numerator F_net and the denominator M_total increase, producing a non-linear hyperbola rather than a straight line. By placing all slotted weights on the cart initially and transferring them one by one to the hanger, M_total remains strictly constant, ensuring that acceleration a is directly proportional to applied force F across the entire data series.

T = M_c \cdot a, \quad m_h g - T = m_h \cdot a \implies m_h g = (M_c + m_h) \cdot a \implies a = \frac{F_{\text{net}}}{M_{\text{total}}}
Why does the tension in the connecting cord T have a magnitude strictly less than the gravitational weight m_h g of the hanging mass while the system is accelerating?

Because the hanging mass is accelerating downward, there must be a net downward force acting on it: F_net = m_h g - T = m_h a > 0. Therefore, the upward string tension T = m_h(g - a) is strictly less than the static weight m_h g.

03Kinematics of Uniform Acceleration: Dual-Photogate Metrology

The measurement of instantaneous linear acceleration requires high-speed chronometric sensing that does not impede the motion. In a dual-photogate timing configuration, an opaque interrupter flag of precision-machined width w is rigidly mounted on the moving cart. As the cart glides along the track, the flag interrupts the narrow infrared beam of the first photogate at position x₁, creating an electrical logic signal of duration Δt₁. Because the flag width w is small (typically 20.0 mm), the average velocity during the transit approximates the instantaneous velocity at photogate 1 to high accuracy: v₁ = w / Δt₁. Similarly, when the flag interrupts the second photogate at position x₂ (separated by distance D = x₂ - x₁), the timer records transit duration Δt₂, yielding v₂ = w / Δt₂. Under the condition of uniform acceleration, the kinematic Torricellian equation connects initial velocity v₁, final velocity v₂, travel distance D, and acceleration a: v₂² = v₁² + 2 a D. Rearranging for acceleration gives a = (v₂² - v₁²) / (2 D) = [ (w/Δt₂)² - (w/Δt₁)² ] / (2 D). Modern digital microprocessor timers automatically perform this calculation internally, displaying the acceleration in real time with microsecond timebase precision.

v_1 = \frac{w}{\Delta t_1}, \quad v_2 = \frac{w}{\Delta t_2}, \quad v_2^2 - v_1^2 = 2 a D \implies a = \frac{v_2^2 - v_1^2}{2 D}
Why is it preferable to calculate acceleration from two photogate velocities v₁ and v₂ rather than measuring a single elapsed time from release from rest?

Releasing from rest introduces uncertainty regarding the exact moment of mechanical detachment and human release friction. Measuring two velocities while the cart is already in smooth motion completely bypasses release transients and zero-time errors.

04Linearization of the Dynamic Governing Equation ($a$ versus $F$)

The theoretical relationship between acceleration and applied force is governed by Newton's Second Law: a = (1 / M_total) · F. This equation is intrinsically linear with respect to applied force F, taking the standard slope-intercept form Y = S · X + b, where Y = a (m s⁻²), X = F (N), theoretical slope S = 1 / M_total (kg⁻¹), and theoretical intercept b = 0. When an ordinary least-squares regression is performed across a series of experimental trials {(F_i, a_i)}, the best-fit slope S minimizes the sum of squared vertical residuals: S = [N ∑(F_i a_i) - ∑(F_i) ∑(a_i)] / [N ∑(F_i²) - (∑ F_i)²]. Once the slope S is determined, the total system inertial mass is recovered by inverting the slope: M_total = 1 / S. The standard error in the slope SE(S) propagates into the standard error of the estimated mass via first-order Taylor expansion: SE(M) = SE(S) / S² = M_total² · SE(S). Furthermore, the fitted intercept b serves as an indispensable diagnostic indicator: if b ≈ 0 within experimental uncertainty, the track friction was correctly compensated; a significantly negative intercept indicates uncompensated mechanical friction, whereas a positive intercept indicates overcompensation (downward track tilt).

Y = S \cdot X + b \quad \text{where } Y = a, \; X = F, \; S = \frac{1}{M_{\text{total}}}, \; b = 0 \implies M_{\text{total}} = \frac{1}{S}
If an a versus F plot yields an inverse slope of M = 1.200 kg with an intercept of b = -0.050 m s⁻², what does this reveal about track friction?

A negative intercept b = -0.050 m s⁻² reveals that an uncompensated frictional resistance force exists, requiring an initial threshold force F_friction = |b| · M ≈ 0.06 N before the cart can begin accelerating.

05Friction Compensation, Track Incline, and Effective Net Force

No physical laboratory track is completely devoid of friction. Mechanical rolling resistance arises from wheel bearing deformation, axle contact shear, and surface irregularities, creating a resistive force F_friction opposing motion. In an uncompensated horizontal track, the equation of motion becomes F_applied - F_friction = M_total · a, which reduces the observed acceleration: a = (F_applied - F_friction) / M_total = (1 / M_total) F_applied - (F_friction / M_total). To eliminate this systematic offset, physicists utilize the technique of dynamic friction compensation. By elevating the rear leveling foot of the track by a tiny angle θ, the component of the cart's gravitational weight acting parallel to the incline, W_parallel = M_cart · g · sin(θ), acts in the forward direction. By carefully adjusting θ until W_parallel exactly balances the rolling resistance (M_cart · g · sin(θ) = F_friction), the cart coasts at constant velocity when pushed without any hanging mass attached (a = 0 when F_applied = 0). When the hanging mass is subsequently connected, the net force accelerating the system is purely the cord tension supplied by the hanging weight, restoring the ideal relation a = F_applied / M_total with zero intercept.

\sum F = F_{\text{applied}} + M_{\text{cart}} g \sin\theta - F_{\text{friction}} = M_{\text{total}} \cdot a \quad \xrightarrow{\text{compensated}} \quad a = \frac{F_{\text{applied}}}{M_{\text{total}}}
How can a student practically verify that a track has been properly friction-compensated without measuring angles?

Place the unweighted cart in the middle of the track and give it a very gentle push in the forward direction. If it glides from one end to the other with constant speed (verified by identical transit times through spaced photogates), the track is perfectly friction-compensated.

06Rotational Inertia of the Pulley and System Mass Corrections

In a real laboratory apparatus, the hanging mass cord passes over a guide pulley of radius R and moment of inertia I_pulley. As the cart accelerates, the pulley must undergo angular acceleration α = a / R to prevent cord slippage. Applying the rotational analogue of Newton's Second Law to the pulley yields τ_net = (T_vertical - T_horizontal) · R = I_pulley · α = I_pulley · (a / R). Consequently, the cord tension is not uniform across the pulley: T_vertical - T_horizontal = (I_pulley / R²) · a. Combining this with the linear equations of motion for the cart and hanging mass gives F_net = m_h g = [ M_cart + m_h + (I_pulley / R²) ] · a. This reveals that the rotational inertia of the pulley contributes an effective equivalent linear mass: M_equiv = I_pulley / R². For a lightweight aluminum spoked pulley of mass 10 g and radius 25 mm, modeling the pulley as a disc (I = 1/2 m_p R²) yields an equivalent mass contribution of M_equiv = 1/2 m_p ≈ 5.0 g (0.005 kg). In high-precision experiments, this small inertia term must be added to the static scale weight of the system, explaining why uncorrected dynamic mass estimates may exceed static scale masses by approximately 0.4%.

F_{\text{net}} = \left(M_{\text{cart}} + m_h + \frac{I_{\text{pulley}}}{R^2}\right) a \implies M_{\text{dynamic}} = M_{\text{static}} + \frac{I_{\text{pulley}}}{R^2}
Why does a massive pulley decrease the linear acceleration of the cart for a given hanging weight?

A portion of the gravitational potential energy released by the descending weight must be converted into rotational kinetic energy (1/2 I ω²) to spin the pulley, leaving less energy available for linear kinetic energy and thereby reducing linear acceleration.

07Non-Inertial Reference Frames, D'Alembert's Principle, and Coordinate Invariance

Newton's Second Law is strictly valid only in inertial (non-accelerating) reference frames, where Newton's First Law holds true. In the laboratory frame of reference, which is anchored to the Earth's surface, the Earth rotates on its axis and orbits the Sun, generating small non-inertial Coriolis and centrifugal accelerations. However, for a terrestrial laboratory experiment spanning 2 meters and lasting less than 2 seconds, these planetary accelerations are on the order of 10⁻⁵ m s⁻², which is negligible compared to the 0.25 to 1.25 m s⁻² accelerations measured here. If one chooses to analyze the cart's dynamics from the non-inertial reference frame of the accelerating cart itself, an observer at rest inside the cart observes the cart to remain stationary (a_rel = 0). To apply Newtonian mechanics in this accelerating frame, D'Alembert introduced the concept of fictitious or inertial forces: a backward inertial force F_inertial = -M_cart · a must be introduced, which exactly balances the forward cord tension: T - M_cart · a = 0. While D'Alembert's principle provides a convenient static reformulation for engineering stress analysis, the laboratory frame remains the fundamental inertial frame in which physical causes (gravitational attraction, string tension) directly produce physical effects (kinematic acceleration).

\vec{F}_{\text{fictitious}} = -m \vec{a}_{\text{frame}}, \quad \sum \vec{F}_{\text{real}} + \vec{F}_{\text{fictitious}} = 0 \quad (\text{D'Alembert's Principle})
If an accelerometer (such as a small liquid level or pendulum) is mounted on the accelerating cart, in which direction will it deflect, and why?

The accelerometer will deflect backward (opposite to the direction of acceleration). In the cart's accelerating reference frame, the backward inertial force pushes the liquid or pendulum bob backward until the restoring force balances it.

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Connect the equations to a measurement.

Theoretical acceleration: a = F / M_total. Linearized relation: a = (1 / M_total) · F. The ordinary least-squares regression extracts the slope S = 1 / M_total, from which total system mass is recovered as M_total = 1 / S. Reference total system mass M_total = 1.200 kg.